Летучий Корабль

Everyone knows that the proper time of a material object flying relative to a resting frame of reference differs from the time of the resting frame of reference and is calculated by the formula.

Where t₀ is the time of the reference frame, V is the velocity of relative motion, C is the velocity of light.

Suppose that two spherical bodies of diameters D₁ and D₂,

where D₁ = D₂ = D and masses m₁ and m₂, where m₁ = m₂ fly towards each other with velocity V₁ and V₂, where V₁ = V₂, as well as proper time t₁ and t_2, where t₁ = t₂ and fly relative to each other at distance R with relative velocity V_REL Figure 1.

If we consider this example from the reference frame of body 1, body 2 is flying relative to body 1 with velocity V₂₁.

From the General Theory of Relativity we know that the expression for the time t₂₁ of body 2 flying relative to the frame of reference of body 1 will look like this.

Just as if we take body 2 as the reference frame, the expressions for time and velocity are identical.

Where

Then the time of body 2 t₂₁ (2) flying with velocity V₂₁ relative to the frame of reference of body 1 with time t₁, is less than time t₁ by the value ∆t.  

Just as for body 1 with time t₁₂ (3) flying with velocity V₁₂ relative to the frame of reference of body 2 with time t₂, is less than time t₂ by the value ∆t.

Based on my assumption, expressed in the article “Relativity of the principle of relativity” that the increment of time ∆t extends to the distance R from the center of mass of the body moving relative to the center of mass of the reference frame with the regularity ∆t/R².

We obtain that the change of the time course ∆t_R in points of space at a distance R from a material body of mass m₂ and velocity V₂ moving relative to a stationary frame of reference, is equal to ∆t_R = ∆ t/R² where

That is, in the general case.

The time course of an object moving relative to the reference frame slows down. Correspondingly, when moving away from such a body, time accelerates its course towards t₀.  Thus, the time course at a distance R from such an object  t_R = t₀ – ∆t_R   

We obtain that the time course at a distance R from the center of body 2 flying relative to body 1 taken as a reference frame is t_R2 and the time course at a distance  R from the center of body 1 will also be t_R1   where  t_R1 = t_R2 = t_R  

Hence the distance L traveled by points  a and b of bodies 1 and 2 flying relative to each other Fig. 2 with velocity V₁ = V₂ = V will be equal to L = V t_R.

From the condition of equality of velocities, masses and sizes of bodies we obtain that, 

L_a1 = L_a2

 L_b1 = L_b2

 L_a1 < L_b1

L_a2 < L_b2

Fig. 2

Where R_a1 = R_a2 = R_a, R_b1 = R_b2 = R_b, R_a = R – 1/2D, R_b = R + 1/2D, R_b = R_a + D,

R_a = R_b – D.

From which it follows that the bodies will describe some arc around each other, Fig. 3.

Let’s try to calculate the radius of the described arc.

The angles ϕ for the arc described by point a and point b of the body will be equal to ϕ_{a =} ϕ_b and from the formula for arc length L = πR ϕ/180 , where ϕ is the angle of the described sector per unit time, R is the radius of the arc.

From the formula for arc length, ϕ is equal to.

Where R_a = R_b – D

From here we can find out the radius described by a body relative to another body.

Or

R_b = R_a + D

The question arises at what velocity of relative motion 

V_REL = V₁₂ = V₂₁ bodies 1 and 2 will rotate around each other while flying uniformly straight and without experiencing any centrifugal forces.

 Let us solve this problem by fitting values of V, R and D, so that the result of calculation of the radius described by the body R_a and R_b is equal to the substituted value.

The results of the calculations are recorded in the table.

	R	1·10-3 m.	1m.	1.8 m.
D/R
1/2		D= 0.5·10-3 m. V=0.0011365·108m/s.	D=0.5 m. V=1.227·108m/s.	D=0.9 m. V=2.7971·108m/s.
1/5		D=0.2·10-3 m. V=0.001211·108m/s.	D=0.2 m. V=1.32295·108m/s.
1/10		D=0.1·10-3 m. V=0.001221·108m/s.	D=0.1 m. V=1.3358·108m/s.
1/100		D=0.01·10-3 m. V=0.001225·108m/s.	D=0.01 m. V=1.3415·108m/s.
1/1000		D=0.001·10-3 m. V=0.0012247·108m/s.	D=0.001 m. V=1.34187·108m/s.

It is clear from the obtained results that the formation of such groups of bodies rotating in time warped space with R value more than 1.8 meters is impossible. The interaction of bodies with parameters R greater than 1.8 meters will only change their flight trajectory towards each other.

There is no doubt that such a structure of curved space can involve in its rotational motion and electromagnetic waves.

The possibility of the existence of such structures can explain the existence of such objects as ball lightning, light lensing, changes in the trajectory of celestial bodies and even the forces holding particles in atoms.

28.06.2025

Свідоцтво: 108775 зареєстровано 20.10.2021